### Jemineth's Phytagoras

Pythagoras: #7 finding the value of a leg

(p.s sorry can't upload the pictures to show the question)

Part A : i=9mm g=5mm h=?

csquared-b/asquared = a/b squared

isquared - gsquared = hsquared

9squared - 5aquared = hsquared

(9 x 9 ) - (5 x 5 ) = h squared

81 - 25 = 56 squared

hsquared = 56

square root = 9.48

This shows that the particular triangle

**a right triangle because the***isn't**value of leg h is greater than the hypotenuse which supposedly is the longest side.*Part B : r=15mm q=11mm s= ?

csquared-b/asquared = a/b squared

rsquared-qsquared = ssquared

15mmsquared-11mmsquared = ssquared

(15x15)-(11x11) = ssquared

225 - 121 = 104 squared

ssquared = 104

squareroot = 10.1

Again this shows that the particular triangle

**a right triangle because the***isn't**value of leg h is greater than the hypotenuse which supposedly is the longest side.*
## 2 comments:

nice job jem but you shouldve put some pictures but still good job.

good job jem, it's okay that you didn't put pictures I would've understand it more, but good job anyways.

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