## Monday, January 4, 2010

### Jemineth's Phytagoras

Pythagoras: #7 finding the value of a leg
(p.s sorry can't upload the pictures to show the question)
Part A : i=9mm g=5mm h=?
csquared-b/asquared = a/b squared
isquared - gsquared = hsquared
9squared - 5aquared = hsquared
(9 x 9 ) - (5 x 5 ) = h squared
81 - 25 = 56 squared
hsquared = 56
square root = 9.48
This shows that the particular triangle isn't a right triangle because the value of leg h is greater than the hypotenuse which supposedly is the longest side.
Part B : r=15mm q=11mm s= ?
csquared-b/asquared = a/b squared
rsquared-qsquared = ssquared
15mmsquared-11mmsquared = ssquared
(15x15)-(11x11) = ssquared
225 - 121 = 104 squared
ssquared = 104
squareroot = 10.1
Again this shows that the particular triangle isn't a right triangle because the value of leg h is greater than the hypotenuse which supposedly is the longest side.

camille,

nice job jem but you shouldve put some pictures but still good job.

Raquel873

good job jem, it's okay that you didn't put pictures I would've understand it more, but good job anyways.